D-Ticket river cruise appears to be confirmed for AVATAR Land at Disney's Animal Kingdom

Jul 08, 2015 in "Pandora - The World of Avatar"

Posted: Wednesday July 8, 2015 10:16am EDT by WDWMAGIC Staff

LA Times reporter Brady MacDonald is reporting that the D-Ticket river cruise will be coming to AVATAR Land when it debuts in 2017.


Although revealed on the originally released permits, the possibility of the second ride being built had been in question. MacDonald from the LA Times has a good track record of accurate park information, so it seems near confirmed that the river cruise will join the E-Ticket Soarin' type ride as the land's attraction lineup.

The river cruise will takes guests on an indoor ride through the illuminated landscape of Pandora, complete with bioluminescent trees and audio-animatronics.

The article goes on to quote Joe Rohde as saying the new E-Ticket banshee flight ride system will be "considerably more thrilling" than the original Soarin', and from James Cameron, Avatar Land will let visitors "live, eat, breathe and smell Pandora."

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TheDisneyParksfanC8Mar 30, 2024

Maybe even Paris as well per Iger's recent words.

TheCoasterNerdMar 18, 2024

Dear God how long ago this was posted - back when I was a simple lurker. But yeahhh its still the most popular land in the park, and so popular its being replicated (or not, or it is, or it isn't, who knows) at DLR. 10 years later. Sorry!

DisneyDrewMay 15, 2017

WDWtravelerMay 04, 2017

Photo update as of Thursday, May 4. The construction wall/barricade has been removed from the new bus transportation shelter. You will note there are only two bus stops (see the upright poles where the bus stops). One bus stop will be sheltered, and one will be in the open. These two bus stops are specifically designed for the double-length buses. The queue fences have been installed, but yet to be painted brown. The new pavement that connects the Animal Kingdom entrance walkway to the new bus transportation shelters. Work crews were busy installing the railings along the walkway. Bales of pine needles in the background for landscaping. 202992

wdisney9000May 04, 2017

Watever helps you sleep at night, bruh......

MisterPenguinMay 04, 2017

lrn2math There is no conflict between what I said and what jgg said.

wdisney9000May 04, 2017

Haha,.....MisterPenguin got schooled.

matt9112May 03, 2017

with no drop and a newer set up i dont think this will have potc issues...with no drop no issue.

Brian SwanMay 03, 2017

I like this guy (or gal)!

MisterPenguinMay 03, 2017

I have a feeling that we'll soon be talking about Schrödinger's family...

jggMay 03, 2017

No misunderstanding here. First of all, you yourself start by deriving the dispatch interval (I bolded it) - which is exactly what @gorillaball said was the one number you need. Since that's the value you need, why not just measure that directly rather than trying to guess at the total # of boats? Second, you've ignored load time and resource contention/starvation. Your hypothetical 5 minute ride will have a different throughput if the load time is 10 seconds vs. 100 seconds - a difference which is already accounted for in the dispatch interval. You can say that your 5 minutes includes load/unload time, but that's not really the common usage of 'ride time' and it's that kind of ambiguous language that leads to people talking past each other. Yeah, if you have the right data you can derive the same result the way you described - these are pretty simple mathematical relationships after all - but it's a really roundabout way of of doing it and requires data that's less easily obtained than just counting off seconds between dispatches. The proper way to model this is as a wave function where each peak represents a ride vehicle. Thus, the period of the wave is the time between dispatches and the inverse of the period (frequency) is the dispatch interval; frequency * capacity = throughput. Modelling this way has a couple of advantages: First, it's fully specified and easily measured. Second, we have lots of well-understood mathematical tools for manipulating, composing, and decomposing waves, which is useful for modelling the system as part of a larger whole.

KrzyKttyMay 03, 2017

I could probably fit my family of 4 in the one row easily, but my husband and I are smallish people with two small kids.

gorillaballMay 03, 2017

The way you explain it there isn't false, you are just going about it a different way (a harder way in my opinion) to get to the same result. For one you are dividing the number of boats (unknown and usually not easy to find) by the ride time (also somewhat unknown, 4-5 minutes). When all someone needs to do is time the average dispatch and you have the answer. So - we aren't totally saying different things. I'm just saying on any new ride the number of vehicles isn't a needed requirement and is usually much harder to find then setting a stop watch and watching dispatch, something that can be done in one viewing of a few minutes. Then if those boats that are dispatched go for 3 minutes or 30 minutes using 3 boats or 300 boats - all information that's not needed because I just viewed boats of X people dispatching every X seconds.

raymusiccityMay 02, 2017

There might be some minor issues with weight distribution! :)